Gujarati
Hindi
Basic Maths
medium

If $F = \frac{2}{{\sin \,\theta  + \sqrt 3 \,\cos \,\theta }}$, then minimum value of $F$ is

A

$0$

B

$-2$

C

$1$

D

$2$

Solution

${F_{\min }} = \frac{2}{{\sqrt {1 + 3} }} = 1$

Standard 11
Physics

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